10=(5x^2)+5x

Solution for 10=(5x^2)+5x equation:

10=(5x^2)+5x

We move all terms to the left:

10-((5x^2)+5x)=0

We get rid of parentheses

-5x^2-5x+10=0

a = -5; b = -5; c = +10;
Δ = b2-4ac
Δ = -52-4·(-5)·10
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-15}{2*-5}=\frac{-10}{-10}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+15}{2*-5}=\frac{20}{-10}
=-2
$